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Question 72
If f(x)=3x5−7x3+2x2+5f ( x ) = 3 x ^ { 5 } - 7 x ^ { 3 } + 2 x ^ { 2 } + 5f(x)=3x5−7x3+2x2+5 , then f′′′(x)=180x2−42f ^ { \prime \prime \prime } ( x ) = 180 x ^ { 2 } - 42f′′′(x)=180x2−42 .
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