Differentiate: $f ( x ) = \sqrt { x } + \frac { 7 } { \sqrt { x } }$
A) 7
B) $\frac { 1 } { 2 \sqrt { x } } + \frac { 7 } { 2 \sqrt { x ^ { 3 } } }$
C) 0
D) $\frac { 1 } { 2 \sqrt { x } } - \frac { 7 } { 2 \sqrt { x ^ { 3 } } }$

Question

Quizplus · Accepted Answer

The derivative of $\sqrt{x}$ is $\frac{1}{2\sqrt{x}}$ and the derivative of $\frac{7}{\sqrt{x}}$ is $-\frac{7}{2\sqrt{x^3}}$.

Differentiate f(x)=x+7xf ( x ) = \sqrt { x } + \frac { 7 } { \sqrt { x } }f(x)=x​+x​7​

Differentiate $f ( x ) = \sqrt { x } + \frac { 7 } { \sqrt { x } }$