Evaluate $\int e ^ { 8 x - 2 } d x$
A) $e ^ { 8 x - 2 } + C$
B) $( 8 x - 2 ) e ^ { 8 x - 2 } + C$
C) $( 8 x - 2 ) C e ^ { 8 x - 2 }$
D) $\frac { e ^ { 8 x - 2 } } { 8 } + C$

Question

Quizplus · Accepted Answer

The integral of $e^{ax+b}$ with respect to $x$ is $\frac{1}{a}e^{ax+b} + C$, where $a$ is a constant, $b$ is a constant, and $C$ is the constant of integration. Applying this rule with $a = 8$ and $b = -2$, the integral becomes $\frac{1}{8}e^{8x-2} + C$.

Evaluate ∫e8x−2dx\int e ^ { 8 x - 2 } d x∫e8x−2dx

Evaluate $\int e ^ { 8 x - 2 } d x$