How Does the Reaction Catalyzed by Malate Dehydrogenase Proceed Despite $\Delta$

How does the reaction catalyzed by malate dehydrogenase proceed despite a $\Delta$ G $\degree$ ' of 29.7 kJ/mol?

A) An elevated [H⁺] allows the reaction to proceed.
B) High levels of NAD⁺ allow the reaction to proceed.
C) Concentrations of oxaloacetate are kept very low by rapid use in the subsequent step.
D) The enzyme is unique in its ability to catalyze the reaction in only one direction.
E) The enzyme catalyzed reaction under cellular conditions has a much smaller energy of activation.