A jogger of mass 66 kg runs at a speed of 2.1 m/s. The de Broglie wavelength of the jogger is
A) $6.5 \times 10 ^ { - 34 }$ m.
B) $8.2 \times 10 ^ { - 35 }$ m.
C) $$1.2 \times 10 ^ { - 35 }$$ m.
D) $4.8 \times 10 ^ { - 36 }$ m.

Question

Quizplus · Accepted Answer

The de Broglie wavelength $\lambda$ is given by $\lambda = \frac{h}{mv}$, where $h$ is Planck's constant ($6.626 \times 10^{-34} \, \text{m}^2\text{kg/s}$), $m$ is the mass of the object, and $v$ is its velocity. Substituting the given values ($m = 66 \, \text{kg}$, $v = 2.1 \, \text{m/s}$), we get $\lambda = \frac{6.626 \times 10^{-34}}{66 \times 2.1} = 4.8 \times 10^{-36} \, \text{m}$.

A Jogger of Mass 66 Kg Runs at a Speed 6.5×10−346.5 \times 10 ^ { - 34 }6.5×10−34

A Jogger of Mass 66 Kg Runs at a Speed $6.5 \times 10 ^ { - 34 }$