A metal having a work function of 4.2 eV is illuminated by light of 200-nm wavelength. The maximum kinetic energy of the photoelectrons is

Question

Quizplus · Accepted Answer

The maximum kinetic energy of the photoelectrons is given by:KE = hc/λ - Φwhere h is Planck's constant, c is the speed of light, λ is the wavelength of the light, and Φ is the work function of the metal.Substituting the given values into the equation, we get:KE = (6.626 x 10^-34 J s)(3 x 10^8 m/s)/(200 x 10^-9 m) - 4.2 eVKE = 2.1 eVTherefore, the maximum kinetic energy of the photoelectrons is 2.1 eV.

A Metal Having a Work Function of 4