X-rays of wavelength 0.400000 nm are scattered from a material. The wavelength of the X-rays scattered at an angle of 45^o to the incident beam is

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Quizplus · Accepted Answer

The change in wavelength of X-rays scattered by a material can be calculated using the Compton scattering formula: $\Delta \lambda = \lambda' - \lambda = \frac{h}{m_e c} (1 - \cos \theta)$, where $h$ is Planck's constant, $m_e$ is the electron mass, $c$ is the speed of light, and $\theta$ is the scattering angle. For a scattering angle of 45 degrees and given constants, the change in wavelength ($\Delta \lambda$) is calculated to be approximately 0.000710 nm. Therefore, the new wavelength ($\lambda'$) is the initial wavelength ($\lambda = 0.400000$ nm) plus the change in wavelength ($\Delta \lambda$), which equals approximately 0.400710 nm.

X-Rays of Wavelength 0