An object moving with a constant velocity of 0.80 c has a mass of $2.78 \times 10 ^ { - 27 } \mathrm {~kg}$ . The rest mass of the object is

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Quizplus · Accepted Answer

The correct answer is A because the rest mass of the object is given by the equation $m_0 = m/\gamma$, where $m$ is the mass of the object moving with a constant velocity and $\gamma$ is the Lorentz factor. The Lorentz factor is given by the equation $\gamma = 1/\sqrt{1 - v^2/c^2}$, where $v$ is the velocity of the object and $c$ is the speed of light. Substituting the given values into these equations, we get:$$m_0 = \frac{2.78 \times 10^{-27} \mathrm{~kg}}{\sqrt{1 - (0.80c)^2/c^2}} = 3.87 \times 10^{-27} \mathrm{~kg}$$

An Object Moving with a Constant Velocity of 0 2.78×10−27 kg2.78 \times 10 ^ { - 27 } \mathrm {~kg}2.78×10−27 kg

An Object Moving with a Constant Velocity of 0 $2.78 \times 10 ^ { - 27 } \mathrm {~kg}$