The Maxwell-Ampere Law can be written as; $\oint \vec { B } \cdot d \vec { s } = \mu _ { 0 } I + \mu _ { 0 } \varepsilon _ { 0 } \frac { d \Phi _ { E } } { d t }$ . The term in the equation that relates to the magnetic field produced by an electric current is
A) $\oint \vec { B } \cdot d \vec { s }$
B) $\mu _ { 0 } I$
C) $\mu _ { 0 } \varepsilon _ { 0 } \frac { d \Phi _ { E } } { d t }$
D) No term in this equation is related to the displacement current.

Question

Quizplus · Accepted Answer

The Answer is B

The Maxwell-Ampere Law Can Be Written As; ∮B⃗⋅ds⃗=μ0I+μ0ε0dΦEdt\oint \vec { B } \cdot d \vec { s } = \mu _ { 0 } I + \mu _ { 0 } \varepsilon _ { 0 } \frac { d \Phi _ { E } } { d t }∮B⋅ds=μ0​I+μ0​ε0​dtdΦE​​

The Maxwell-Ampere Law Can Be Written As; $\oint \vec { B } \cdot d \vec { s } = \mu _ { 0 } I + \mu _ { 0 } \varepsilon _ { 0 } \frac { d \Phi _ { E } } { d t }$