A simple RL circuit contains a 4.0- $\Omega$ resistor and an 32-H inductor. The circuit's time constant is
A) 130 s.
B) 8.0 s.
C) 4.0 s.
D) 2.0 s.
E) 0.13 s.

Question

Quizplus · Accepted Answer

The time constant $\tau$ of an RL circuit is given by $\tau = \frac{L}{R}$, where $L$ is the inductance and $R$ is the resistance. Substituting the given values, $\tau = \frac{32\,H}{4.0\,\Omega} = 8.0\,s$.

A Simple RL Circuit Contains a 4 Ω\OmegaΩ Resistor and an 32-H Inductor

A Simple RL Circuit Contains a 4 $\Omega$ Resistor and an 32-H Inductor