The maximum torque of a 100-turn loop of wire that has an area of 0.15 m² and is carrying 1.5 A of current in a uniform magnetic field of 2.0 T is A) zero. B) 5.0 N·m. C) 15 N·m. D) 45 N·m.

Question

Quizplus · Accepted Answer

The maximum torque (τ) on a current loop in a magnetic field is given by τ = n * I * A * B, where n is the number of turns, I is the current, A is the area, and B is the magnetic field. Substituting the given values: τ = 100 * 1.5 * 0.15 * 2.0 = 45 N·m.

The Maximum Torque of a 100-Turn Loop of Wire That