An electron is accelerated to an energy of 100 eV and then enters a magnetic field of strength 0.15 T. The resulting radius of the electron's trajectory is A) 2.2 * 10^-4 m. B) 3.3 *10^-4 m. C) 4.4 * 10^-4 m. D) 5.5 * 10^-4 m.

Question

Quizplus · Accepted Answer

The correct answer is A because the radius of the electron's trajectory is given by r = mv/qB, where m is the mass of the electron, v is its velocity, q is its charge, and B is the magnetic field strength. Plugging in the given values, we get r = (9.11 * 10^-31 kg)(1.60 * 10^6 m/s)/(1.60 * 10^-19 C)(0.15 T) = 2.2 * 10^-4 m.

An Electron Is Accelerated to an Energy of 100 EV