The Law of Biot-Savart is
A) $\mathrm { d } \mathbf { B } = - \left( \mu _ { 0 } / 4 \pi \right) I \mathrm {~d} \mathbf { l } \times \mathbf { r } ^ { 2 }$
B) $\mathrm { d } \mathbf { B } = - \left( \mu _ { 0 } / 4 \pi \right) I \mathrm {~d} \mathbf { l } \times \mathbf { r }$
C) $\mathrm { d } \mathbf { B } = \left( \mu _ { 0 } / 4 \pi \right) I \mathrm {~d} \mathbf { l } \times \mathbf { r } ^ { 3 }$
D) $\mathrm { d } \mathbf { B } = \left( \mu _ { 0 } / 4 \pi \right) I \mathrm {~d} \mathbf { l } \times \mathbf { r } ^ { 2 }$

Question

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The Answer of The Law of Biot-Savart is
A) $\mathrm { d } \mathbf { B } = - \left( \mu _ { 0 } / 4 \pi \right) I \mathrm {~d} \mathbf { l } \times \mathbf { r } ^ { 2 }$
B) $\mathrm { d } \mathbf { B } = - \left( \mu _ { 0 } / 4 \pi \right) I \mathrm {~d} \mathbf { l } \times \mathbf { r }$
C) $\mathrm { d } \mathbf { B } = \left( \mu _ { 0 } / 4 \pi \right) I \mathrm {~d} \mathbf { l } \times \mathbf { r } ^ { 3 }$
D) $\mathrm { d } \mathbf { B } = \left( \mu _ { 0 } / 4 \pi \right) I \mathrm {~d} \mathbf { l } \times \mathbf { r } ^ { 2 }$

The Law of Biot-Savart Is A) dB=−(μ0/4π)I dl×r2\mathrm { d } \mathbf { B } = - \left( \mu _ { 0 } / 4 \pi \right) I \mathrm {~d} \mathbf { l } \times \mathbf { r } ^ { 2 }dB=−(μ0​/4π)I dl×r2

The Law of Biot-Savart Is
A) $\mathrm { d } \mathbf { B } = - \left( \mu _ { 0 } / 4 \pi \right) I \mathrm {~d} \mathbf { l } \times \mathbf { r } ^ { 2 }$