A parallel-plate capacitor has capacitance of $6.5 \times 10 ^ { - 8 }$ F and charge of $8.1 \times 10 ^ { - 11 }$ C. The potential across the plates is
A) 1.2 mV.
B) 520 mV.
C) 802 V.
D) 8.0 V.

Question

Quizplus · Accepted Answer

The potential across the plates of a capacitor is given by the equation V = Q/C, where V is the potential, Q is the charge, and C is the capacitance. Substituting the given values into the equation, we get V = (8.1 x 10^-11 C) / (6.5 x 10^-8 F) = 1.2 mV.

A Parallel-Plate Capacitor Has Capacitance Of 6.5×10−86.5 \times 10 ^ { - 8 }6.5×10−8

A Parallel-Plate Capacitor Has Capacitance Of $6.5 \times 10 ^ { - 8 }$