Three capacitors, A, B, and C, are connected in series to a source. The effective capacitance as seen by the source is
A) $A B C / ( A + B + C )$
B) $( A + B + C ) / ( A B C )$
C) $A + B + C$
D) $A B C / ( A B + B C + C A )$

Question

Quizplus · Accepted Answer

The formula for the effective capacitance ($C_{eff}$) of capacitors in series is given by the reciprocal of the sum of the reciprocals of the individual capacitances. This can be mathematically represented as $1/C_{eff} = 1/A + 1/B + 1/C$, which simplifies to $C_{eff} = ABC / (AB + BC + CA)$.

Three Capacitors, A, B, and C, Are Connected in Series ABC/(A+B+C)A B C / ( A + B + C )ABC/(A+B+C)

Three Capacitors, A, B, and C, Are Connected in Series $A B C / ( A + B + C )$