A parallel-plate capacitor, having a vacuum dielectric, has capacitance of 620 $\mu$ F. A Plexiglas dielectric, $k = 3.4$ , is inserted between the plates. The new capacitance is
A) 180 $\mu$ F.
B) 1400 $\mu$ F.
C) 2100 $\mu$ F.
D) 620 $\mu$ F.

Question

Quizplus · Accepted Answer

The capacitance of a capacitor with a dielectric is given by $C' = kC$, where $k$ is the dielectric constant. Here, $C' = 3.4 \times 620 \mu F = 2108 \mu F$, which rounds to 2100 $\mu$ F.

A Parallel-Plate Capacitor, Having a Vacuum Dielectric, Has Capacitance of 620