The magnitude of the electric field 10.0 cm from an infinitely long charged wire that has a linear charge density of 1.1 $\mu$ C/m is

Question

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The electric field $E$ around an infinitely long charged wire is given by the formula $E = \frac{\lambda}{2\pi\epsilon_0 r}$, where $\lambda$ is the linear charge density, $\epsilon_0$ is the vacuum permittivity ($8.85 \times 10^{-12} \, \text{C}^2/\text{N}\cdot\text{m}^2$), and $r$ is the distance from the wire. Given $\lambda = 1.1 \times 10^{-10} \, \text{C/m}$ and $r = 0.1 \, \text{m}$, substituting these values into the formula gives an electric field magnitude of approximately $2.0 \times 10^5 \, \text{N/C}$.

The Magnitude of the Electric Field 10 μ\muμ C/m Is A) 1

The Magnitude of the Electric Field 10 $\mu$ C/m Is
A) 1