A 13.6-N force is acting on an electrical charge. At the location of the charge, the 3.1-N/C electric field points in the opposite direction of the force. The charge is

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The force on a charge due to an electric field is given by $F = qE$, where $F$ is the force, $q$ is the charge, and $E$ is the electric field. Given that the force and the electric field are in opposite directions, the charge must be negative. The magnitude of the charge can be calculated as $q = \frac{F}{E} = \frac{13.6 \, \text{N}}{3.1 \, \text{N/C}} = 4.4 \, \text{C}$, thus the charge is $-4.4 \, \text{C}$.

A 136-N Force Is Acting on an Electrical Charge +4.4C. + 4.4 \mathrm { C } \text {. }+4.4C.

A 136-N Force Is Acting on an Electrical Charge $+ 4.4 \mathrm { C } \text {. }$