An infinite flat sheet has a surface charge density of $- 15.3$ nC/m $2$ The magnitude of the electric field at a distance of 5.3 cm above the infinite sheet is

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Quizplus · Accepted Answer

The electric field due to an infinite sheet with surface charge density $\sigma$ is given by $E = \frac{\sigma}{2\varepsilon_0}$. Substituting $\sigma = -15.3 \times 10^{-9} \, \text{C/m}^2$ and $\varepsilon_0 = 8.85 \times 10^{-12} \, \text{C}^2/\text{N}\cdot\text{m}^2$, we find $E = \frac{15.3 \times 10^{-9}}{2 \times 8.85 \times 10^{-12}} \approx 860 \, \text{N/C}$. The distance from the sheet does not affect the magnitude of the electric field.

An Infinite Flat Sheet Has a Surface Charge Density Of -