A charged particle of mass $10 ^ { - 26 }$ kg is released in a uniform electric field of 1.3 pN/C. The acceleration of the charge is 9100 m/s $2$ Therefore the charge is

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The force on the charge is given by $ F = ma $. Substituting the given values, $ F = 10^{-26} \times 9100 $. The force is also given by $ F = qE $, where $ E = 1.3 \times 10^{-12} $ N/C. Equating the two expressions for force, $ q = \frac{10^{-26} \times 9100}{1.3 \times 10^{-12}} = 70 \times 10^{-12} $ C, which is 70 pC.

A Charged Particle of Mass 10−2610 ^ { - 26 }10−26

A Charged Particle of Mass $10 ^ { - 26 }$