A heat engine has an efficiency of 0.25 when it receives 250 J of heat. The amount of heat exhausted by the engine is

Question

Quizplus · Accepted Answer

The efficiency of a heat engine is given by the formula $ \eta = \frac{W}{Q_{in}} $, where $ \eta $ is the efficiency, $ W $ is the work done (or energy output), and $ Q_{in} $ is the heat input. Given an efficiency of 0.25 (or 25%) and a heat input of 250 J, the work done by the engine is $ 0.25 \times 250 = 62.5 $ J. The heat exhausted is the difference between the heat input and the work done, which is $ 250 J - 62.5 J = 187.5 J $. Since none of the options exactly match this result due to rounding, the closest option is 190 J.

A Heat Engine Has an Efficiency of 0