The change in entropy when 55 g of ice at 0°C melts (the heat of fusion is 3.34 * 10⁵ J/kg) to water at 0°C is

Question

Quizplus · Accepted Answer

The change in entropy ($\Delta S$) for a process can be calculated using the formula $\Delta S = \frac{Q}{T}$, where $Q$ is the heat absorbed or released during the process and $T$ is the temperature in Kelvin at which the process occurs. For the melting of ice at 0°C (273.15 K), $Q$ can be calculated by multiplying the mass of the ice (55 g or 0.055 kg) by the heat of fusion (3.34 x $10^5$ J/kg), and then $\Delta S$ is found by dividing $Q$ by the temperature in Kelvin. This results in a positive change in entropy, indicating an increase in disorder as ice melts to water.

The Change in Entropy When 55 G of Ice at 0°C