During an isobaric (constant pressure) expansion, the volume of an ideal gas increases from 0.15 m³ to 0.35 m³. The pressure during the expansion is 150 kPa. The work done by the system is

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Quizplus · Accepted Answer

The work done by the system during an isobaric process can be calculated using the formula $W = P \Delta V$, where $W$ is the work done, $P$ is the pressure, and $\Delta V$ is the change in volume. Given that the pressure $P = 150$ kPa and the volume change $\Delta V = 0.35 - 0.15 = 0.20$ m$^3$, the work done is $W = 150 \times 10^3 \times 0.20 = 30,000$ J or $30$ kJ. Since the volume increases, the work is done by the system on the surroundings, making it positive.

During an Isobaric (Constant Pressure) Expansion, the Volume of an Ideal