A barrel that is 0.250 m in radius and 1.00 m in height is completely submerged in water. The buoyant force acting on the barrel is
A) 1920 N.
B) 3850 N.
C) 7700 N.
D) Hold on! The contents of the barrel are required to answer this question.

Question

Quizplus · Accepted Answer

The buoyant force can be calculated using Archimedes' principle, which states that the buoyant force is equal to the weight of the displaced fluid. The volume of the barrel is $V = \pi r^2 h = \pi (0.250)^2 (1.00) = 0.19635 \, \text{m}^3$. The weight of the water displaced is equal to the volume of water displaced times the density of water ($1000 \, \text{kg/m}^3$) times the acceleration due to gravity ($9.8 \, \text{m/s}^2$), giving a buoyant force of $0.19635 \, \text{m}^3 \times 1000 \, \text{kg/m}^3 \times 9.8 \, \text{m/s}^2 = 1924.23 \, \text{N}$, which is closest to 1920 N. The contents of the barrel are irrelevant to the calculation of the buoyant force.

A Barrel That Is 0