The intensity level of a 0.5-W/m $2$ signal is
A) 270 dB.
B) 150 dB.
C) 117 dB.
D) 88 dB.

Question

Quizplus · Accepted Answer

The intensity level $ L $ in decibels (dB) of a sound of intensity $ I $ in watts per meter squared (W/m$^2$) is given by the formula $ L = 10 \log_{10} \left( \frac{I}{I_0} \right) $, where $ I_0 = 1 \times 10^{-12} $ W/m$^2$ is the reference intensity level. Plugging in the given intensity $ I = 0.5 $ W/m$^2$, we get $ L = 10 \log_{10} \left( \frac{0.5}{1 \times 10^{-12}} \right) = 117 $ dB.

The Intensity Level of a 0 222 Signal Is A) 270 DB

The Intensity Level of a 0 $2$ Signal Is
A) 270 DB