Two masses, M_A = 1.0 kg and M_B = 2.5 kg, are attached at the opposite ends of a rod 1.0 m in length. The mass of the rod is 1.5 kg. The moment of inertia of the system about an axis perpendicular to the rod passing through its center is A) 1.0 kg^.m². B) 1.5 kg^.m². C) 2.0 kg^.m². D) 2.5 kg^.m².

Question

Quizplus · Accepted Answer

The moment of inertia of the system about an axis perpendicular to the rod passing through its center is:I = I_A + I_B + I_rod= (1.0 kg)(0.5 m)² + (2.5 kg)(0.5 m)² + (1.5 kg)(0.5 m)²= 1.0 kg^.m²

Two Masses, MA = 1

Two Masses, M_A = 1