A billiard ball of mass 0.16 kg, radius 2.86 cm, and moment of inertia about its diameter of 5.23 $\times$ 10^-5 kg·m² moves on a table at 1.5 m/s. The rotational kinetic energy of the ball is

Question

Quizplus · Accepted Answer

The rotational kinetic energy (KE_rot) can be calculated using the formula KE_rot = 1/2 * I * ω^2, where I is the moment of inertia and ω is the angular velocity. Given the ball's speed (v = 1.5 m/s) and radius (r = 2.86 cm = 0.0286 m), we can find ω using ω = v/r. Substituting the given values, ω = 1.5 / 0.0286 = 52.45 rad/s. Then, KE_rot = 1/2 * 5.23e-5 * (52.45)^2 = 0.072 J.

A Billiard Ball of Mass 0 ×\times× 10-5 Kg·m2 Moves on a Table at 1

A Billiard Ball of Mass 0 $\times$ 10^-5 Kg·m² Moves on a Table at 1