The Moon has a mass of 7.35 $\times$ 10²²kg and a mean radius of 1.74 $\times$ 10⁶m. The velocity required by the Apollo landing capsule to escape from the gravitational attraction of the Moon is

Question

Quizplus · Accepted Answer

The escape velocity from a celestial body can be calculated using the formula $v = \sqrt{\frac{2GM}{r}}$, where $v$ is the escape velocity, $G$ is the gravitational constant ($6.674 \times 10^{-11} \, \text{m}^3\text{kg}^{-1}\text{s}^{-2}$), $M$ is the mass of the celestial body, and $r$ is the radius of the celestial body. Using the given mass and radius of the Moon, the calculation yields an escape velocity of approximately 2.38 km/s, which rounds to 2.40 km/s, making option A correct.

The Moon Has a Mass of 7 ×\times× 1022 kg and a Mean Radius of 1

The Moon Has a Mass of 7 $\times$ 10²²kg and a Mean Radius of 1