A solid ball having a mass of 2.6 kg and a radius of 0.2 m is placed at the top of an incline. The incline makes an angle of $\theta$ = 51º with the horizontal. The ball is then released and rolls without slipping down the incline. The acceleration of the ball's center of mass along the incline is

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Quizplus · Accepted Answer

The acceleration of a solid ball rolling without slipping down an incline is given by $a = \frac{5}{7}g \sin(\theta)$. Substituting $g = 9.8 \, \text{m/s}^2$ and $\theta = 51^\circ$, we get $a \approx 5.4 \, \text{m/s}^2$.

A Solid Ball Having a Mass of 2 θ\thetaθ = 51º with the Horizontal

A Solid Ball Having a Mass of 2 $\theta$ = 51º with the Horizontal