A spring with a force constant of 5.0 N/m is used to suspend a 2.0-N weight. The displacement of the mass is
A) 0.40 m.
B) 10 m.
C) 2.5 m.
D) -2.5 m.

Question

Quizplus · Accepted Answer

The displacement can be found using Hooke's Law, $F = kx$, where $F$ is the force (2.0 N), $k$ is the spring constant (5.0 N/m), and $x$ is the displacement. Solving for $x$, we get $x = \frac{F}{k} = \frac{2.0\, \text{N}}{5.0\, \text{N/m}} = 0.40\, \text{m}$.

A Spring with a Force Constant of 5