A 1500-kg car on a snow-covered road starts from rest and accelerates at a constant rate for 12 seconds until traveling at 40 m/s. What is the frictional force imparted to the car by the snow-covered road?
A) 15,000 N
B) 7500 N
C) 5000 N
D) 2500 N

Question

Quizplus · Accepted Answer

The acceleration can be calculated using the formula $ a = \frac{\Delta v}{\Delta t} = \frac{40 \, \text{m/s}}{12 \, \text{s}} \approx 3.33 \, \text{m/s}^2 $. The frictional force is then $ F = ma = 1500 \, \text{kg} \times 3.33 \, \text{m/s}^2 = 5000 \, \text{N} $.

A 1500-Kg Car on a Snow-Covered Road Starts from Rest