Let vector A = -2i - j + 2k. The unit vector parallel to vector A is
A) -i - j + k.
B) -(2/3)i - (1/3)j + (2/3)k.
C) i + j - k.
D) none of the above.

Question

Quizplus · Accepted Answer

To find a unit vector parallel to vector A, we first calculate the magnitude of A: |A| = sqrt((-2)^2 + (-1)^2 + 2^2) = sqrt(4 + 1 + 4) = sqrt(9) = 3. Then, the unit vector is obtained by dividing each component of A by its magnitude, resulting in: (-2/3)i - (1/3)j + (2/3)k.

Let Vector a = -2i - J + 2k