15.00 mL of 0.100 M NaOH is required to completely neutralize 25.00 mL of an HCl solution. What is the concentration of the HCl solution?

Question

Quizplus · Accepted Answer

The correct answer is A because the number of moles of NaOH is equal to the number of moles of HCl. Therefore, the concentration of the HCl solution can be calculated as follows:Moles of NaOH = (0.100 M) x (15.00 mL) = 1.50 mmolMoles of HCl = 1.50 mmolConcentration of HCl = (1.50 mmol) / (25.00 mL) = 0.0600 M

1500 ML of 0