A 155-L helium balloon is heated from 24.0 C to 38.0 C. What would be its new volume assuming the pressure remains constant?

Name: A 155-L helium balloon is heated from 24.0 C to 38.0 C. What would be its new volume assuming the pressure remains constant?
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Question

Quizplus · Accepted Answer

Using Charles's Law (V1/T1 = V2/T2), where temperatures must be in Kelvin. Convert temperatures: 24.0 C = 297 K and 38.0 C = 311 K. Solve for V2: V2 = V1 * (T2/T1) = 155 L * (311 K / 297 K) ≈ 162 L.

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