If 25.0 mL of 3.0 M HCl are diluted to give a final volume of 150 mL, what is the new concentration?

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Quizplus · Accepted Answer

The new concentration can be calculated using the dilution formula $C_1V_1 = C_2V_2$, where $C_1$ and $V_1$ are the initial concentration and volume, and $C_2$ and $V_2$ are the final concentration and volume, respectively. Substituting the given values: $3.0 \, \text{M} \times 25.0 \, \text{mL} = C_2 \times 150 \, \text{mL}$. Solving for $C_2$ gives $C_2 = 0.50 \, \text{M}$.

If 250 ML of 3