A coordination complex has the empirical formula, Cr(NH₃)₅Cl₃, and has a limited solubility in water. The reaction of a solution of this complex with silver nitrate solution consistently produces two millimoles of silver chloride for every millimole of the Cr(NH₃)₅Cl₃. Reaction with aqueous H₂SO₄ or HCl results in no free ammonia in the solution. Which complex ion is consistent with these observations?Hint: Compare the stoichiometries of the reactant and product complexes.

Question

Quizplus · Accepted Answer

The complex [Co(NH₃)₅Cl]Cl₂ will release two chloride ions when dissolved in water, which can react with silver nitrate to form two millimoles of silver chloride per millimole of complex. The lack of free ammonia upon reaction with acids suggests that all ammonia ligands are coordinated to the metal center.

A Coordination Complex Has the Empirical Formula, Cr(NH3)5Cl3, and Has

A Coordination Complex Has the Empirical Formula, Cr(NH₃)₅Cl₃, and Has