How many coulombs of charge are required for the reduction of 0.20 mol of Cr³⁺ ions to Cr metal?

Name: How many coulombs of charge are required for the reduction of 0.20 mol of Cr 3+ ions to Cr metal?
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Question

Quizplus · Accepted Answer

To reduce Cr³⁺ to Cr, 3 moles of electrons are needed per mole of Cr³⁺. For 0.20 mol of Cr³⁺, 0.60 mol of electrons are needed. Using Faraday's constant (96500 C/mol), the charge required is 0.60 mol × 96500 C/mol = 5.8 × 10⁴ coulombs.

How Many Coulombs of Charge Are Required for the Reduction