Using the Standard Entropy Values:
C₂H₄(g), S° = +219 $\rarr$ C₂H₆(g)
A)+120

Using the standard entropy values:
C₂H₄(g) , S° = +219.8 J mol^-1 K^-
H₂(g) , S° = +130.6 J mol^-1 K^-1
C₂H₆(g) , S° = +229.5 J mol^-1 K^-1
Calculate the standard entropy change, S°, for the reaction:C₂H₄(g) + H₂(g) $\rarr$ C₂H₆(g)

A) +120.9 J mol^-1 K^-1
B) -98.9 J mol^-1 K^-1
C) -120.9 J mol^-1 K^-1
D) +140.3 J mol^-1 K^-1
E) +579.9 J mol^-1 K^-1