Using the Data:
C₂H₆(g) $\Delta$ H°_f = -84 $\Delta$ H°_f = -394

Using the data:
C₂H₆(g) , $\Delta$ H°_f = -84.5 kJ mol^-1, S° = +229.5 J mol^-1 K^-1
CO₂(g) , $\Delta$ H°_f = -394.0 kJ mol^-1, S° = +213.6 J mol^-1 K^-1
H₂O(l) , $\Delta$ H°_f = -286.0 kJ mol^-1, S° = +69.96 J mol^-1 K^-1
O₂(g) , $\Delta$ H°_f = 0.00 kJ mol^-1, S° = +205 J mol^-1 K^-1
Calculate the maximum amount of work that can be obtained, at 25.0 °C, from the process:C₂H₆(g) + 7 O₂(g) $\rarr$ 4 CO₂(g) + 6 H₂O(l) , per mole of C₂H₆

A) 1426 kJ mol^-1
B) 1469 kJ mol^-1
C) 1654 kJ mol^-1
D) 2938 kJ mol^-1
E) 3029 kJ mol^-1