For PbCl₂, K_sp = 1

For PbCl₂, K_sp = 1.7 × 10^-5. Will a precipitate of PbCl₂ form when 200 mL of 3.0 × 10^-2 M Pb(NO₃) ₂ solution is added to 300 mL of 5.0 × 10^-2 M KCl?Hint: Find the concentration of each ion in the insoluble compound, and use those to find Q.

A) yes, the ion product, Q > K_sp
B) no, the ion product, Q < K_sp
C) no, the ion product, Q = K_sp
D) yes, the ion product, Q < K_sp
E) no, because the ion product, Q > K_sp