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The Formation Constant for the Bis(thiosulfato)argentate(I)ion Is 2

Question 77

Multiple Choice

The formation constant for the bis(thiosulfato) argentate(I) ion is 2.0 × 1013, while the solubility product constant for silver bromide is 5.0 × 10-13. What would be the equilibrium constant for the reaction below?AgBr(s) + 2 S2O32-(aq) The formation constant for the bis(thiosulfato) argentate(I) ion is 2.0 × 10<sup>13</sup>, while the solubility product constant for silver bromide is 5.0 × 10<sup>-</sup><sup>13</sup>. What would be the equilibrium constant for the reaction below?AgBr(s) + 2 S<sub>2</sub>O<sub>3</sub><sup>2</sup><sup>-</sup>(aq)    Ag(S<sub>2</sub>O<sub>3</sub>) <sub>2</sub><sup>3</sup><sup>-</sup>(aq) + Br<sup>-</sup>(aq)  A) 2.0 × 10<sup>13</sup> B) 5.0 × 10<sup>-</sup><sup>1</sup> C) 4.0 × 10<sup>25</sup> D) 5.0 × 10<sup>-</sup><sup>13</sup> E) 10 Ag(S2O3) 23-(aq) + Br-(aq)


A) 2.0 × 1013
B) 5.0 × 10-1
C) 4.0 × 1025
D) 5.0 × 10-13
E) 10

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