Toluic acid, HC₈H₇O₂, has an ionization constant with the value: K_a = 1.23 × 10^-5. Calculate the value of pK_b for the conjugate base of toluic acid.

Name: Toluic acid, HC 8 H 7 O 2 , has an ionization constant with the value: K a = 1.23 × 10 -5 . Calculate the value of pK b for the conjugate base of toluic acid.
Brand: Quizplus
Rating: 4.8 (49 reviews)

Question

Quizplus · Accepted Answer

pKb is calculated using the relation pKa + pKb = 14. Given pKa = -log(1.23 × 10^-5) = 4.91, so pKb = 14 - 4.91 = 9.09.

Toluic Acid, HC8H7O2, Has an Ionization Constant with the Value

Toluic Acid, HC₈H₇O₂, Has an Ionization Constant with the Value