A solution is made by taking 100.0 mL of 4.0 × 10^-3 molar NaOH(aq)and mixing in 10.0 mL of 4.0 × 10^-2 molar HCl(aq). A small portion was tested using thymol blue indicator, for which the pK_In = 8.8, and the colors are yellow for HIn, and blue for In^-. What color would be observed?

Question

Quizplus · Accepted Answer

The NaOH and HCl will react to form water and NaCl. The moles of NaOH are 0.004 mol, and the moles of HCl are 0.0004 mol. After the reaction, there will be excess NaOH, making the solution basic. However, the pH will be less than 8.8, so the solution will be yellow due to the thymol blue indicator.

A Solution Is Made by Taking 100