A solution is made by taking 100.0 mL of 2.0 × 10-2 molar NaOH(aq) and mixing in 50.0 mL of 3.0 × 10-2 molar HCl(aq) . A small portion was tested using tyrolian blue indicator, for which the pKIn = 12.5, and the colors are blue for HIn, and yellow for In-. What color would be observed as a result of the testing?
A) blue
B) green
C) yellow
D) orange
E) red
Correct Answer:
Verified
Q102: The pH at the equivalence point of
Q103: The pH at the equivalence point of
Q104: Given the following two solutions:
0.200 M HC2H3O2(aq)with
Q105: Given the following two solutions:
0.200 M HCl(aq)
0.200
Q106: A mixture is made by mixing 50.0
Q108: A solution is made by taking 2.42
Q109: The pH at the equivalence point of
Q110: 50.0 mL of 0.10 M HCl(aq)was added
Q111: 20.0 mL of 0.10 M H2SO4(aq)was added
Q112: 40.0 mL of 0.20 M HCl(aq)was added
Unlock this Answer For Free Now!
View this answer and more for free by performing one of the following actions
Scan the QR code to install the App and get 2 free unlocks
Unlock quizzes for free by uploading documents