At 60 ^°C the value of K_w is 9.5 × 10^-14. Considering this, what is the pOH of a 2.00 × 10^-3 M HCl(aq)solution at this temperature?

Question

Quizplus · Accepted Answer

The concentration of HCl is 2.00 × 10^-3 M, which means [H⁺] = 2.00 × 10^-3 M. Using the relation [H⁺][OH⁻] = Kw, we find [OH⁻] = Kw / [H⁺] = (9.5 × 10^-14) / (2.00 × 10^-3) = 4.75 × 10^-11 M. The pOH is calculated as -log[OH⁻] = -log(4.75 × 10^-11) ≈ 10.32.

At 60 °C the Value of Kw Is 9

At 60 ^°C the Value of K_w Is 9