A solution is prepared by mixing 0.3355 moles of NaNO₃ (84.995 g mol^-1)with 235.0 g of water (18.015 g mol^-1). Its density is 1.0733 g mL^-1. What is the molarity of the solution?

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Quizplus · Accepted Answer

The correct answer is D.The molarity of the solution is calculated by dividing the number of moles of solute by the volume of the solution in liters. The volume of the solution is calculated by dividing the mass of the solution by its density.The number of moles of solute is 0.3355 moles. The mass of the solution is 235.0 g + (0.3355 moles * 84.995 g mol^-1) = 320.54 g. The density of the solution is 1.0733 g mL^-1. Therefore, the volume of the solution is 320.54 g / 1.0733 g mL^-1 = 298.7 mL.The molarity of the solution is 0.3355 moles / 0.2987 L = 1.123 M.

A Solution Is Prepared by Mixing 0