What is the expected freezing point of a solution that contains 25.0 g of fructose, C₆H₁₂O₆, in 250.0 g of H₂O? For water, K_f = 1.86 °C m^-1.

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The freezing point depression can be calculated using the formula ΔTf = i * Kf * m, where i is the van't Hoff factor (1 for fructose, a non-electrolyte), Kf is the freezing point depression constant (1.86 °C m^-1 for water), and m is the molality of the solution. First, calculate the molality: moles of fructose = 25.0 g / 180.18 g/mol = 0.1387 mol; molality = 0.1387 mol / 0.250 kg = 0.5548 m. Then, ΔTf = 1 * 1.86 °C m^-1 * 0.5548 m = 1.03°C. The freezing point of the solution is 0°C - 1.03°C = -1.03°C.

What Is the Expected Freezing Point of a Solution That