Solved

For Two Ions with Charges Q1 and Q2 Separated by Distance

Question 13

Multiple Choice

For two ions with charges q1 and q2 separated by distance r, the potential energy canbe calculated from Coulomb's law: E = For two ions with charges q<sub>1</sub> and q<sub>2</sub> separated by distance r, the potential energy canbe calculated from Coulomb's law: E =   Calculate the energy released when 1 mole NaCl is formed if the constant k = 1.11 × 10<sup>-10</sup> C<sup>2</sup>/J·m, the charge Na<sup>+</sup> = +1 e, and the charge on Cl<sup>-</sup> is -1 e, e = 1.602 × 10<sup>-19</sup> C, and <sup> </sup>   A) +308 kJ/mol B) +8.20 kJ/mol C) -297 kJ/mol D) -494 kJ/mol E) -371 kJ/mol Calculate the energy released when 1 mole NaCl is formed if the constant k = 1.11 × 10-10 C2/J·m, the charge Na+ = +1 e, and the charge on Cl- is -1 e, e = 1.602 × 10-19 C, and For two ions with charges q<sub>1</sub> and q<sub>2</sub> separated by distance r, the potential energy canbe calculated from Coulomb's law: E =   Calculate the energy released when 1 mole NaCl is formed if the constant k = 1.11 × 10<sup>-10</sup> C<sup>2</sup>/J·m, the charge Na<sup>+</sup> = +1 e, and the charge on Cl<sup>-</sup> is -1 e, e = 1.602 × 10<sup>-19</sup> C, and <sup> </sup>   A) +308 kJ/mol B) +8.20 kJ/mol C) -297 kJ/mol D) -494 kJ/mol E) -371 kJ/mol


A) +308 kJ/mol
B) +8.20 kJ/mol
C) -297 kJ/mol
D) -494 kJ/mol
E) -371 kJ/mol

Correct Answer:

verifed

Verified

Unlock this answer now
Get Access to more Verified Answers free of charge

Related Questions

Unlock this Answer For Free Now!

View this answer and more for free by performing one of the following actions

qr-code

Scan the QR code to install the App and get 2 free unlocks

upload documents

Unlock quizzes for free by uploading documents