In barium sulfide, the number of electrons in the Lewis symbol for the barium is zero, while for the sulfide ion, it is 2.
Correct Answer:
Verified
Q129: The lattice energy is the energy released
Q130: The lattice energy of Al2O3 is greater
Q131: When electrons are removed from a given
Q132: The octet rule does not work well
Q133: The electron configuration for the Sb3+ ion
Q135: There are covalent bonds in the Lewis
Q136: The energy of the bond holding two
Q137: The maximum number of electrons that can
Q138: The F-O bond is more polar than
Q139: Br2 will oxidize NaI, but not NaF
Unlock this Answer For Free Now!
View this answer and more for free by performing one of the following actions
Scan the QR code to install the App and get 2 free unlocks
Unlock quizzes for free by uploading documents