A 2500 Gram Pellet of Lead (Specific Heat = 0

A 25.00 gram pellet of lead (specific heat = 0.128 J g^-1 °C^-1) at 25 °C is added to 95.3 g of boiling water (specific heat of 4.18 J g^-1 °C^-1) at 100 °C in an insulated cup. What is the expected final temperature of the water?

A) 26.6 °C
B) 62.5 °C
C) 84.4 °C
D) 99.4 °C
E) 100.6 °C